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Nuclear Gradient

The derivative of the total energy with respect to nuclear positions is needed for structure optimization and in molecular dynamics, that is

$\displaystyle {\partial E_{\rm total} \over \partial {\bf R}_{I,s}} = {\partial...
... {\bf R}_{I,s}} + {\partial E_{\rm ES} \over \partial {\bf R}_{I,s}} \enspace ,$ (217)

as the kinetic energy $ E_{\rm kin}$ and the exchange and correlation energy $ E_{\rm xc}$ do not depend directly on the atomic positions, the relevant parts are
$\displaystyle {\partial E^{\rm PP}_{\rm local} \over \partial {\bf R}_{I,s}}$ $\displaystyle =$ $\displaystyle - \Omega \sum_{\bf G} i{\bf G}_{s}   \Delta V_{\rm local}^{I}({\bf G})
  S_{I}({\bf G})   n^\star({\bf G})$ (218)
$\displaystyle {\partial E^{\rm PP}_{\rm nonlocal} \over \partial {\bf R}_{I,s}}$ $\displaystyle =$ $\displaystyle \sum_{i} f_{i} \sum_{\alpha, \beta \in {I}} \left\{
\left(F_{I,i}...
...ar \over \partial {\bf R}_{I,s}}
h_{\alpha, \beta}^{I} F_{I,i}^{\beta} \right\}$ (219)
$\displaystyle {\partial E_{\rm ES} \over \partial {\bf R}_{I,s}}$ $\displaystyle =$ $\displaystyle -   \Omega \sum_{{\bf G} \neq 0} i {\bf G}_{s}   {n^\star_{\rm ...
..._{I}({\bf G})
+ {\partial E_{\rm ovrl} \over \partial {\bf R}_{I,s}} \enspace .$ (220)

The contribution of the projectors of the non-local pseudopotentials is calculated from

$\displaystyle {\partial F_{I,i}^{\alpha} \over \partial {\bf R}_{I,s}} = - {1 \...
..., P_{\alpha}^{I} ({\bf G})   S_{I}({\bf G})   c_{i}^\star({\bf G}) \enspace .$ (221)

Finally, the real space part contribution of the Ewald sum is
$\displaystyle {\partial E_{\rm ovrl} \over \partial {\bf R}_{I,s}}$ $\displaystyle =$ $\displaystyle \mathop{{\sum}'}_{J} \sum_{\bf L} \left\{
{Z_{I} Z_{J} \over \ver...
... \over
\sqrt{{{\rm R}_{I}^{\rm c}}^2+{{\rm R}_{J}^{\rm c}}^2} } \right] \right.$  
    $\displaystyle \left. + {2 \over \sqrt{\pi}}
{1 \over \sqrt{{{\rm R}_{I}^{\rm c}...
...\over
\sqrt{{{\rm R}_{I}^{\rm c}}^2+{{\rm R}_{J}^{\rm c}}^2} } \right] \right\}$  
    $\displaystyle \times ({\bf R}_{I,s} - {\bf R}_{J,s} - {\bf L}_{s}) \enspace .$ (222)

The self energy $ E_{\rm self}$ is independent of the atomic positions and does not contribute to the forces.


next up previous contents index
Next: Fast Fourier Transforms Up: Total Energy and Gradients Previous: Wavefunction Gradient   Contents   Index
Costas Bekas 2008-09-04